Octet 类是从元组JavaTuples。由于此Octet 是一个泛型类,因此它可以包含任何类型的值。由于Octet 是一个元组,因此它也具有JavaTuples的所有特征:

  • Typesafe
  • 永恒的
  • 可迭代
  • Serializable
  • Comparable(实现Comparable <Tuple>)
  • 实现equals()hashCode()
  • 实现toString()

Octet 类声明

public final class Octet<A, B, C, D, E, F, G, H> extends Tuple
implements IValue0<A>, IValue1<B>, IValue2<C>, IValue3<D>, IValue4<E>, 
                                            IValue5<F, IValue6<G, IValue7<H>

Octet 类层次结构

Object
  ↳ org.javatuples.Tuple
      ↳ org.javatuples.Octet<A, B, C, D, E, F, G, H>

创建Octet元组

  • 来自构造函数语法
    Octet<A, B, C, D, E, F, G, H> octet = 
        new Octet<A, B, C, D, E, F, G, H>
            (value1, value2, value3, value4, value5, value6, value7, value8);

    示例

    // Below is a Java program to create
    // a Octet tuple from Constructor
    
    import java.util.*;
    import org.javatuples.Octet;
    
    class GfG {
        public static void main(String[] args)
        {
            Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> octet
                = Octet.with(Integer.valueOf(1),
                             Integer.valueOf(2),
                             Integer.valueOf(3),
                             Integer.valueOf(4),
                             Integer.valueOf(5),
                             Integer.valueOf(6),
                             Integer.valueOf(7),
                             Integer.valueOf(8));
    
            System.out.println(octet);
        }
    }
    

    输出:

    [1,2,3,4,5,6,7,8]
    
  • 使用with()方法:with()方法是JavaTuples库提供的函数,用于使用这些值实例化对象。语法
    Octet <type1,type2,type3,type4,type5,type6,type7> octet = 
        Octet.with(value1,value2,value3,value4,value5,value6,value7,value8);
    

    示例

    // Below is a Java program to create
    // a Octet tuple from with() method
    
    import java.util.*;
    import org.javatuples.Octet;
    
    class GfG {
        public static void main(String[] args)
        {
            Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> octet
                = Octet.with(Integer.valueOf(1),
                             Integer.valueOf(2),
                             Integer.valueOf(3),
                             Integer.valueOf(4),
                             Integer.valueOf(5),
                             Integer.valueOf(6),
                             Integer.valueOf(7),
                             Integer.valueOf(8));
    
            System.out.println(octet);
        }
    }
    

    输出:

    [1,2,3,4,5,6,7,8]
    
  • 来自其他集合:fromCollection()方法用于从集合创建元组,而fromArray()方法用于从数组创建。集合/数组必须与Tuple具有相同的类型,并且集合/数组中的值的数量必须与Tuple类匹配。语法
    Octet <type1,type2,type3,type4,type5,type6,type7> octet = 
        Octet.fromCollection(collectionWith_8_value);
    
    Octet <type1,type2,type3,type4,type5,type6,type7> octet = 
        Octet.fromArray(arrayWith_8_value);
    

    示例

    // Below is a Java program to create
    // a Octet tuple from Collection
    
    import java.util.*;
    import org.javatuples.Octet;
    
    class GfG {
        public static void main(String[] args)
        {
            // Creating Octet from List
            List<Integer> list = new ArrayList<Integer>();
            list.add(1);
            list.add(2);
            list.add(3);
            list.add(4);
            list.add(5);
            list.add(6);
            list.add(7);
            list.add(8);
    
            Octet<Integer, Integer, Integer, Integer, Integer, Integer, Integer> octet
                = Octet.fromCollection(list);
    
            // Creating Octet from Array
            Integer[] arr = { 1, 2, 3, 4, 5, 6, 7, 8 };
    
            Octet<Integer, Integer, Integer, Integer, Integer, Integer, Integer> otherOctet
                = Octet.fromArray(arr);
    
            System.out.println(octet);
            System.out.println(otherOctet);
        }
    }
    

    输出:

    [1,2,3,4,5,6,7,8]
    [1,2,3,4,5,6,7,8]
    

获得Octet 的值

getValueX()方法可用于获取索引X处的元组中的值。元组中的索引从0开始。因此索引X处的值表示位置X + 1处的值。

语法

Octet<type1, type2, type3, type4, type5, type6, type7> octet = 
    new Octet<type1, type2, type3, type4, type5, type6, type7>
        (value1, value2, value3, value4, value5, value6, value7, value8);

type1 val1 = octet.getValue0();

示例

// Below is a Java program to get
// a Octet value

import java.util.*;
import org.javatuples.Octet;

class GfG {
    public static void main(String[] args)
    {
        Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> octet
            = Octet.with(Integer.valueOf(1),
                         Integer.valueOf(2),
                         Integer.valueOf(3),
                         Integer.valueOf(4),
                         Integer.valueOf(5),
                         Integer.valueOf(6),
                         Integer.valueOf(7),
                         Integer.valueOf(8));

        System.out.println(octet.getValue0());
        System.out.println(octet.getValue2());
    }
}

输出:

1
3

设置Octet 的值

由于元组是不可变的,这意味着无法修改索引处的值。因此,JavaTuples提供setAtX(value),它在索引X处创建一个带有新值的元组副本,并返回该元组。

语法

Octet<type1, type2, type3, type4, type5, type6, type7> octet = 
    new Octet<type1, type2, type3, type4, type5, type6, type7>
      (value1, value2, value3, value4, value5, value6, value7, value8);

Octet<type1, type2, type3, type4, type5, type6, type7> 
    otherOctet = octet.setAtX(value);

示例

// Below is a Java program to set
// a Octet value

import java.util.*;
import org.javatuples.Octet;

class GfG {
    public static void main(String[] args)
    {
        Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> octet
            = Octet.with(Integer.valueOf(1),
                         Integer.valueOf(2),
                         Integer.valueOf(3),
                         Integer.valueOf(4),
                         Integer.valueOf(5),
                         Integer.valueOf(6),
                         Integer.valueOf(7),
                         Integer.valueOf(8));

        Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> otherOctet
            = octet.setAt3(40);

        System.out.println(otherOctet);
    }
}

输出:

[1,2,3,40,5,6,7,8]

添加Octet 的值

可以在addAtX()方法的帮助下添加值,其中X表示要添加值的索引。此方法返回元素的元组,比被调用的元组多一个。

语法

Octet<type1, type2, type3, type4, type5, type6, type7> octet = 
    new Octet<type1, type2, type3, type4, type5, type6, type7>
        (value1, value2, value3, value4, value5, value6, value7, value8);

Octet<type 1, type 2, type 3, type 4, type 5, type 6, type 7> octet = 
    octet.addAtx(value);

示例

// Below is a Java program to add
// a value

import java.util.*;
import org.javatuples.Octet;
import org.javatuples.Ennead;

class GfG {
    public static void main(String[] args)
    {
        Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> octet
            = Octet.with(Integer.valueOf(1),
                         Integer.valueOf(2),
                         Integer.valueOf(3),
                         Integer.valueOf(4),
                         Integer.valueOf(5),
                         Integer.valueOf(6),
                         Integer.valueOf(7),
                         Integer.valueOf(8));

        Ennead<Integer, Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> ennead
            = octet.addAt8(9);

        System.out.println(ennead);
    }
}

输出:

[1,2,3,4,5,6,7,8,9]

在Octet中搜索

可以使用预定义的方法contains()在元组中搜索元素。无论值是否存在,它都返回一个布尔值。

语法

Octet<type1, type2, type3, type4, type5, type6, type7> octet = 
    new Octet<type1, type2, type3, type4, type5, type6, type7>
        (value1, value2, value3, value4, value5, value6, value7, value8);

boolean res = octet.contains(value2);

示例

// Below is a Java program to search
// a value in a Octet

import java.util.*;
import org.javatuples.Octet;

class GfG {
    public static void main(String[] args)
    {
        Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> octet
            = Octet.with(Integer.valueOf(1),
                         Integer.valueOf(2),
                         Integer.valueOf(3),
                         Integer.valueOf(4),
                         Integer.valueOf(5),
                         Integer.valueOf(6),
                         Integer.valueOf(7),
                         Integer.valueOf(8));

        boolean exist = octet.contains(5);
        boolean exist1 = octet.contains(false);

        System.out.println(exist);
        System.out.println(exist1);
    }
}

输出:

true
false

通过Octet迭代

因为Octet实现了Iterable <Object>接口。这意味着它们可以以与集合或数组相同的方式进行迭代。

语法

Octet<type1, type2, type3, type4, type5, type6, type7> octet = 
    new Octet<type1, type2, type3, type4, type5, type6, type7>
            (value1, value2, value3, value4, value5, value6, value7, value8);

for (Object item : octet) {
        ...
}

示例

// Below is a Java program to iterate
// a Octet

import java.util.*;
import org.javatuples.Octet;

class GfG {
    public static void main(String[] args)
    {
        Octet<Integer, Integer, Integer.Integer, Integer, Integer, Integer, Integer> octet
            = Octet.with(Integer.valueOf(1),
                         Integer.valueOf(2),
                         Integer.valueOf(3),
                         Integer.valueOf(4),
                         Integer.valueOf(5),
                         Integer.valueOf(6),
                         Integer.valueOf(7),
                         Integer.valueOf(8));

        for (Object item : octet)
            System.out.println(item);
    }
}

输出:

1
2
3
4
5
6
7
8
 
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